Y = 3x + 2 melalui titik (6, -1)
cari gradien dulu
y = 3x + 2
y = mx + c
m = 3
persamaan tegak lurus
m1 . m2 = -1
3 . m2 = -1
m2 = -1/3
persamaan garis melalui titik (6,-1) m = -1/3
rumus -> y-y1 = m(x-x1)
jawab :
y-y1 = m(x-x1)
y-(-1) = -1/3(x-6)
y+1 = -1/3x + 2
y = -1/3x +2-1
y = -1/3x + 1
smoga mbntu ...